Question
Write the correct number in the given boxes from the following $A. P.$
$70, 60, 50, 40, . . .$
Here $t _1=\square, t _2=\square, t _3=\square, \ldots$
$\therefore  a =\square, d =\square$

Answer

$70,60,50,40, \ldots$
First term a $=70$
Second term $t_1=60$
Third term $t _2=50$
Fourth term $t_3=40$
We know that $d=t_{n+1}-t_n$
Thus, $t_2-t_1=50-60=-10$
$t_3-t_2=40-50=-10$
Thus. $d=-10$

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