Question
Write the name and structural formula of the compound obtained when ethanol is heated at 443 K with excess of cone. $H _2 SO _4$. Also write chemical equation for the reaction stating the role of cone. $H _2 SO _4$ in it.

Answer

The name of the compound formed is Ethene and its structural formula is$\ \ \ \ \ \ \text{H} \ \ \ \text{H} \\ \ \ \ \ \ \ \ \text{|} \ \ \ \ \ \text{|} \\ \text{H} {-} \text{C} {=} \text{C} {-} \text{H}$
Chemical equation:
$\text{C}_{2}\text{H}_{5}\text{OH}\xrightarrow[443 \text{K}]{\text{Conc. H}_{2}\text{SO}_{4}} \text{C}\text{H}_{2} {=} \text{C}\text{H}_{2} + \text{H}_{2}\text{O} \\ \ \text{Ethanol} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Ethane}$
Role of $H _2 SO _4$: It works as a catalyst to initiate the reaction to lose water molecule to form alkene.

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