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Introduction of Trigonometry and its Application — Maths STD 10 — Question

CBSE BoardEnglish MediumSTD 10MathsIntroduction of Trigonometry and its Application1 Mark
Question
Write ‘True’ or ‘False’ and justify your answer.
$\sqrt{(1-\cos^2\theta)\sec^2\theta}=\tan\theta$
✓

Answer

True.LHS $=\sqrt{(1-\cos^2\theta)\sec^2\theta}=\sqrt{\sin^2\theta.\frac{1}{\cos^2\theta}}$
$=\sqrt{\frac{\sin^2\theta}{\cos^2\theta}}=\tan\theta=$ RHS
Hence, the given expression is true.

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