x at x = 1 - Vidyadip

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x at x = 1

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We have, $\text{f(x)}=\text{x}$ $\because\text{f}'\text{(a)}=\lim\limits_{\text{h}\rightarrow0}\frac{\text{f(a+h)}-\text{f(a)}}{\text{h}}$ $\therefore\text{f}'\text{(1)}=\lim\limits_{\text{h}\rightarrow0}\frac{\text{f(1+h)}-\text{f(1)}}{\text{h}}$ $=\lim\limits_{\text{h}\rightarrow0}\frac{\text{1+h}-1}{\text{h}}$ $=\lim\limits_{\text{h}\rightarrow0} 1$ $\therefore\text{f}'(1)=1$

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