\(\Delta S_{\text {reaction }}=-50-\left(\frac{3}{2} \times 40+\frac{1}{2} \times 60\right)\)\(=-40 \mathrm{Jmol}^{-1}\)
\(\Delta \mathrm{C}=\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S}\)
at equilibrium \(\Delta G=0\) \(\Delta H=T \Delta S\)
\(30 \times 10^{3}=T \times 40\)
\(\Rightarrow T=750 \mathrm{K}\)