MCQ
$x=2, y=3$ is a solution of the linear equation:
- ✓$2 x+3 y-13=0$
- B$3 x+2 y-31=0$
- C$2 x-3 y+13=0$
- D$2 x+3 y+13=0$
✓
Answer
Correct option: A.
$2 x+3 y-13=0$
(a)
We have,
$
x=2 \text { and } y=3
$
Let us substitute the above values in the equation $2 x+3 y-13=0$, we get
$
\begin{aligned}
LHS & =(2 \times 2)+(3 \times 3)-13=4+9-13=13-13=0 \\
RHS & =0
\end{aligned}
$
Since, LHS $=$ RHS, the required linear equation is $2 x+3 y-13=0$.
Hence, the correct option is (a).
We have,
$
x=2 \text { and } y=3
$
Let us substitute the above values in the equation $2 x+3 y-13=0$, we get
$
\begin{aligned}
LHS & =(2 \times 2)+(3 \times 3)-13=4+9-13=13-13=0 \\
RHS & =0
\end{aligned}
$
Since, LHS $=$ RHS, the required linear equation is $2 x+3 y-13=0$.
Hence, the correct option is (a).
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