MCQ
$Xe{F_6}$ on hydrolysis gives
- ✓$Xe{O_3}$
- B$XeO$
- C$Xe{O_2}$
- D$Xe$
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$Fe|FeSO_4$ $E^o_{OP} = 0.44\, V$ $(a = 0.1\, M)$
$(I)$ $C_6H_5-CH-Br$
$(II)$ $\begin{array}{*{20}{c}}
{{C_6}{H_5} - CH - {C_2}{H_5}} \\
{|\,\,\,} \\
{Br}
\end{array}$
$(a)$ saline hydrides produce $H_2$ gas when reacted with $H_2O.$
$(b)$ reaction of $LiAH_4$ with $BF_3$ leads to $B_2H_6.$
$(c)$ $PH_3$ and $CH_4$ are electron - rich and electron-precise hydrides, respectively.
$(d)$ $HF$ and $CH_4$ are called as molecular hydrides.
