MCQ
$XeF_6$ on hydrolysis produces
- A$XeOF_4$
- B$XeO_2F_2$
- ✓$XeO_3$
- D$XeO_2$
$XeF_6 + 3H_2O \to XeO_3 + 6HF$
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$\therefore$ reactant $(A)$ is