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6.1. Equilibrium - 1 (chemical Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.1. Equilibrium - 1 (chemical Equilibrium)1 Mark
MCQ
$XY_2$ dissociates $X{Y_2}(g)\,\rightleftharpoons \,XY{\kern 1pt} (g)\, + \,Y\,(g)$  When the initial presure of $XY_2$ is $600\,mm\,Hg,$ the total equilibrium pressure is $800 \,mm\,Hg.$ Calculate $K$ for the reaction. Assuming that the volume of the system remains unchanged.
  • A
    $50$
  • ✓
    $100$
  • C
    $166.6$
  • D
    $400$
✓

Answer

Correct option: B.
$100$
b
                      $X{Y_2} \rightleftharpoons XY + Y$

Initial               $P$             $0$        $0$

Final               $P-x$        $x$       $x$

Initial $P=600\, \mathrm{mm}$ $Hg$. Final $P=800\, \mathrm{mm}$ $Hg$

Total moles $\propto$ final $P .$

$\therefore P-x+x+x \propto 800$

$600-x+x+x \propto 800$

$\mathrm{x}=200\, \mathrm{mm}\, \mathrm{Hg}$

$\mathrm{K}=\frac{\mathrm{x} \times \mathrm{x}}{\mathrm{P}-\mathrm{x}}=\frac{200 \times 200}{400}=100 \,\mathrm{Hg}$

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