MCQ
$y^2-2 x y+b^2=0$ તો $\frac{d y}{d x}=\ldots \ldots . . .(x \neq y)$
  • A
    $\frac{y}{x-y}$
  • $\frac{y}{y-x}$
  • C
    $\frac{x}{x-y}$
  • D
    $\frac{x}{y-x}$

Answer

Correct option: B.
$\frac{y}{y-x}$
$\frac{y}{y-x}$

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