Question
यदि $A = \left( {\begin{array}{*{20}{c}}3&2\\0&1\end{array}} \right)$, तो ${({A^{ - 1}})^3}$=
$ \Rightarrow $ ${({A^{ - 1}})^3} = \frac{1}{{27}}\,{\left( {\begin{array}{*{20}{c}}1&{ - 2}\\0&3\end{array}} \right)^3} = \frac{1}{{27}}\,\left( {\begin{array}{*{20}{c}}1&{ - 26}\\0&{27}\end{array}} \right)$.
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