Question
यदि $AX = B$ के लिये, $B = \left[ \begin{array}{l}9\\52\\0\end{array} \right]$ तथा ${A^{ - 1}} = \left[ {\begin{array}{*{20}{c}}3&{ - \frac{1}{2}}&{ - \frac{1}{2}}\\{ - 4}&{\,\,\,\frac{3}{4}}&{\,\,\,\,\frac{5}{4}}\\2&{ - \frac{1}{4}}&{ - \frac{3}{4}}\end{array}} \right]$, तो $X =$