Question
यदि $\Delta = \left| {\,\begin{array}{*{20}{c}}a&{a + b}&{a + b + c}\\{3a}&{4a + 3b}&{5a + 4b + 3c}\\{6a}&{9a + 6b}&{11a + 9b + 6c}\end{array}\,} \right|$ जहाँ $a = i,b = \omega ,c = {\omega ^2}$, तब $\Delta $का मान होगा
$a[{a^2} + ab - 2{a^2} - ab] = - {a^3} = i$.
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