Question
यदि $y = {\log _{\sin x}}(\tan x),$ तब ${\left( {\frac{{dy}}{{dx}}} \right)_{\pi /4}} = $
==> $\frac{{dy}}{{dx}} = \frac{{(\log \sin x)\left( {\frac{{{{\sec }^2}x}}{{\tan x}}} \right) - (\log \tan x)(\cot x)}}{{{{(\log \sin x)}^2}}}$
==> ${\left( {\frac{{dy}}{{dx}}} \right)_{\pi /4}} = \frac{{ - 4}}{{\log 2}}$, (हल करने पर).
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.