Young's modules of material of a wire of length ' $L$ ' and cross-sectional area $A$ is $Y$. If the length of the wire is doubled and cross-sectional area is halved then Young's $modules$ will be :
  • A $\frac{Y}{4}$
  • B $4\  Y$
  • C $\mathrm{Y}$
  • D $2\  \mathrm{Y}$
JEE MAIN 2024, Diffcult
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