M.C.Q. [1 Marks Each]

MCQ 511 Mark

The number $4,70,394$ is standard form is written as:

✓
$4.70394 \times 10^5$
B
$4.70394 \times 10^4$
C
$47.0394 \times 10^4$
D
$4703.94 \times 10^2$

Answer

Correct option: A.

$4.70394 \times 10^5$

Since, $4,70,394 = 4.70394 \times 100000 = 4.70394 \times 10^5$
So, the number $4,70,394$ in standard form is written as $4.70394 \times 10^5$
Hence, the correct alternative is option $(a)$.

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MCQ 521 Mark

Which of the following is not equal to $\big(\frac{-5}{4}\big)^{4}$?

A
$\frac{(-5)^{4}}{4^{4}}$
B
$\frac{-5^{4}}{(4)^{4}}$
✓
$-\frac{5^{4}}{4^{4}}$
D
$\big(-\frac{5}{4}\big)\times\big(-\frac{5}{4}\big)\times\big(-\frac{5}{4}\big)\times\big(-\frac{5}{4}\big)$

Answer

Correct option: C.

$-\frac{5^{4}}{4^{4}}$

We know that, $\big(\frac{\text{p}}{\text{q}}\big)^{\text{m}}=\frac{\text{p}^{\text{m}}}{\text{q}^{\text{m}}}$
So, $\big(\frac{-5}{4}\big)^{4}=\frac{(-5)^{4}}{(4)^{4}}$
or $\big(\frac{-5}{4}\big)^{4}=\frac{(5)^{4}}{(-4)^{4}}$
or $\big(\frac{-5}{4}\big)^{4}=\big(\frac{-5}{4}\big)\times\big(\frac{-5}{4}\big)\times\big(\frac{-5}{4}\big)$
Hence, option $(c)$ is not equal to $1$.

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MCQ 531 Mark

Mark $(\checkmark)$ tick against the correct answer in the following:
$(6^{-1}-8^{-1})^{-1}=?$

A
$-\frac{1}{2}$
B
$-2$
C
$\frac{1}{24}$
✓
$24$

Answer

Correct option: D.

$24$

$\because (6^{-1}-8^{-1})=\Big(\frac{1}{6}+-\frac{1}{8}\Big)^{-1}$
$=\Big(\frac{4-3}{24}\Big)^{-1}$
$=\Big(\frac{1}{24}\Big)^{-1}=24$

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MCQ 541 Mark

Expanded form of $(xy)^4$ is -

✓
$(-xy) \times (-xy) \times (-xy) \times (-xy)$
B
$4 \times (-xy)$
C
$(-xy) \times (-xy)$
D
$(-xy) \times (-xy) \times (-xy)$

Answer

Correct option: A.

$(-xy) \times (-xy) \times (-xy) \times (-xy)$

$(xy)^4= (xy)^{1+1+1+1} = (-xy) \times (-xy) \times (-xy) \times (-xy)$

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MCQ 551 Mark

Find the value of the given expression: $\Bigg(\Big(\frac{3}{4}\Big)^1-\Big(\frac{1}{4}\Big)^1\Bigg)^{-1}$

A
$\frac{3}{8}$
✓
$\frac{-3}{8}$
C
$\frac{8}{3}$
D
$\frac{-8}{3}$

Answer

Correct option: B.

$\frac{-3}{8}$

$\Big(\frac{3}{4}\Big)^{-1}-\Big(\frac{1}{4}\Big)-1^{-1}=\frac{4}{3}-4^{-1}=\frac{-8^{-1}}{3}=\frac{-3}{8}$

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MCQ 561 Mark

Mark $(\checkmark)$ tick against the correct answer in the following:
$\Big(\frac{-1}{2}\Big)^{-6}=?$

A
$-64$
✓
$64$
C
$\frac{1}{64}$
D
$\frac{-1}{64}$

Answer

Correct option: B.

$64$

$\because \Big(\frac{-1}{2}\Big)^{-6}=(-2)^6$
$=(-2)\times(-2)\times(-2)\times(-2)\times(-2)\times(-2)$
$=64$

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MCQ 571 Mark

The expanded form of $x^4$ is -

A
$x \times 4$
B
$x \times x \times x$
✓
$x \times x \times x \times x$
D
$x + x + x + x$

Answer

Correct option: C.

$x \times x \times x \times x$

The expanded form of $x^4$is $x ∗ x ∗ x ∗ x$

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MCQ 581 Mark

Mark $(\checkmark)$ against the correct answer in the following:
Which of the following numbers is in standard form?

A
$32.63 \times 10^4$
B
$326.3 \times 10^3$
✓
$3.263 \times 10^5$
D
None of these.

Answer

Correct option: C.

$3.263 \times 10^5$

A given number is said to be in standarf form if it can be expressed as $k \times 10^n,$ where $k$ is a real number such that $1\leq\text{k}<10$ and $n$ is a positive integer.
For example: $3.263 \times 10^5$

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MCQ 591 Mark

In standard form, the number $72105.4$ is written as $7.21054 × 10^n$ where n is equal to:

A
$2$
B
$3$
✓
$4$
D
$5$

Answer

Correct option: C.

$4$

We know that, if the given number is greater than or equal to $10,$ then the power of $10$ (i.e. $n$) is a positive integer equal to the number of places the decimal point has been shifted.
Hence, $72105.4$
$= 7.21054 \times 10^4$

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MCQ 601 Mark

Mark $(\checkmark)$ tick against the correct answer in the following:
$\bigg\{\Big(\frac{3}{4}\Big)^{-1}-\Big(\frac{1}{4}\Big)^{-1}\bigg\}^{-1}=?$

A
$\frac{3}{8}$
✓
$\frac{-3}{8}$
C
$\frac{8}{3}$
D
$\frac{-8}{3}$

Answer

Correct option: B.

$\frac{-3}{8}$

$\bigg\{\Big(\frac{3}{4}\Big)^{-1}-\Big(\frac{1}{4}\Big)^{-1}\bigg\}^{-1}=\Big(\frac{4}{3}-\frac{4}{1}\Big)^{-1}$
$=\Big(\frac{4-12}{3}\Big)^{-1}=\Big(\frac{-8}{3}\Big)^{-1}$
$=\frac{-3}{8}$

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MCQ 611 Mark

The mixed radical $\sqrt[5]{486}$ can be expressed as:

✓
$3\sqrt[5]{2}$
B
$4\sqrt[5]{2}$
C
$3\sqrt2$
D
$4\sqrt2$

Answer

Correct option: A.

$3\sqrt[5]{2}$

$\sqrt[5]{486}=\sqrt[5]{3^5.2}$
$=\sqrt[5]2\sqrt[5]{3^5}$
$=3\sqrt[5]{2}$

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MCQ 621 Mark

Exponential form of $(-2) \times (-2) \times (-2)$

A
$3^3$
B
$(-3)^3$
✓
$(-2)^3$
D
None of these

Answer

Correct option: C.

$(-2)^3$

$-2 \times -2 \times -2 = (-2)^{ 1 + 1 + 1} = -2^3$

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MCQ 631 Mark

$(6^{-1} - 8^{-1})^{-1 }=$

A
$\frac{1}{24}$
✓
$24$
C
$-24$
D
$-\frac{1}{24}$

Answer

Correct option: B.

$24$

$(6^{-1}-8^{-1})^{-1}=$
$=\Big(\frac{1}{6}-\frac{1}{8}\Big)^{-1}$ $\Big(\text{As},\text{x}^{-1}=\frac{1}{\text{x}}\Big)$
$=\Big(\frac{4-3}{24}\Big)^{-1}$
$=\Big(\frac{1}{24}\Big)^{-1}$
$=\frac{24}{1}$ $\Big(\text{As},\text{x}^{-1}=\frac{1}{\text{x}})$
$=24$
Hence, the correct alternative is option $(b)$.

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MCQ 641 Mark

$[(-3)^2]^3$ is equal to:

A
$(-3)^8$
✓
$(-3)^6$
C
$(-3)^5$
D
$(-3)^{23}$

Answer

Correct option: B.

$(-3)^6$

We know that, if $‘a’$ is a rational number, m and n are natural numbers, then.
$(a^m)^n = a^{m \times n}$
So, $[(-3)^2 ]^3$
$= (-3)^{2 \times 3}$
$= (-3)^6$

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MCQ 651 Mark

Find m so that $(-3)^{m + 1} × (-3)^5 = (-3)^7$

A
$2$
B
$3$
✓
$1$
D
None of these

Answer

Correct option: C.

$1$

$(-3)^{m + 1} × (-3)^5 = (-3)^7$
$(-3)^{m + 1 + 5} = (-3)^7$
$(-3)^{m + 6} = (-3)^7$
On both the sides powers have the same base different from $1$ and $-1,$
so their exponents must be equal.
Therefore, $m + 6 = 7$
or $m = 7 - 6 = 1$

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MCQ 661 Mark

If $2^n = 4096,$ then $2^{n-5} =$

✓
$128$
B
$64$
C
$256$
D
$32$

Answer

Correct option: A.

$128$

Since,
As, $2^n = 4096$
$\Rightarrow 2^n = 2^{12}$
Comparing the exponent of both the sides, we get:
$n = 12$
Now, $2^{n-5} = 2^{12-5}$
$= 2^7$
$= 128$
Hence, the correct alternative is option $(a)$.

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MCQ 671 Mark

$\bigg\{\Big(\frac{5}{3}\Big)^{15}\bigg\}^0$ is equal to:

A
$\frac{5}{3}$
B
$\frac{3}{5}$
✓
$1$
D
$\text{None of these}$

Answer

Correct option: C.

$1$

Anything raised to the power of $0$ equals $1$

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MCQ 681 Mark

Mark $(\checkmark)$ tick against the correct answer in the following:
$\bigg\{\Big(\frac{1}{2}\Big)^{-3}-\Big(\frac{1}{2}\Big)^{-3}\bigg\}\div\Big(\frac{1}{4}\Big)^{-3}=?$

✓
$\frac{19}{64}$
B
$\frac{64}{19}$
C
$\frac{27}{16}$
D
None of these.

Answer

Correct option: A.

$\frac{19}{64}$

$\because \bigg\{\Big(\frac{1}{2}\Big)^{-3}-\Big(\frac{1}{2}\Big)^{-3}\bigg\}\div\Big(\frac{1}{4}\Big)^{-3}$
$=[(3)^3-(2)^3]\div(4)^3$
$=(27-8)\div64$
$=19\div64=\frac{19}{64}$

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MCQ 691 Mark

In $y^c, y$ is called the:

A
Power
B
Exponent
✓
Base
D
Alphabet

Answer

Correct option: C.

Base

In $y^c, y$ is called Base.
$\Rightarrow yc$ in this expression $y$ is base and $c$ is power.

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MCQ 701 Mark

Find the value of m, if $(16^8)^m= (16)^0$

✓
$0$
B
$1$
C
$16$
D
$8$

Answer

Correct option: A.

$0$

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MCQ 711 Mark

The value of $21^0$ is _____:

A
$0$
B
$21$
✓
$1$
D
$−21$

Answer

Correct option: C.

$1$

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MCQ 721 Mark

Mark $(\checkmark)$ tick against the correct answer in the following:
$\bigg\{\Big(\frac{1}{3}\Big)^2\bigg\}^4=?$

A
$\Big(\frac{1}{3}\Big)^6$
✓
$\Big(\frac{1}{3}\Big)^8$
C
$\Big(\frac{1}{3}\Big)^{16}$
D
$\Big(\frac{1}{3}\Big)^{24}$

Answer

Correct option: B.

$\Big(\frac{1}{3}\Big)^8$

$\because \bigg\{\Big(\frac{1}{3}\Big)^2\bigg\}^4=\Big(\frac{1}{3}\Big)^{2\times4}$
$=\Big(\frac{1}{3}\Big)^8$

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MCQ 731 Mark

Convert $62000+39000$ to scietific form:

✓
$1.01 \times 105$
B
$1.1 \times 105$
C
$1.01\times 104$
D
$1.1 \times 104$

Answer

Correct option: A.

$1.01 \times 105$

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MCQ 741 Mark

$a^0= 1$ is true for all a except:

A
$−1$
B
negative integers
✓
$0$
D
$1$

Answer

Correct option: C.

$0$

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MCQ 751 Mark

The value of $\big[(-2)^{(-2)}\big]^{(-3)}$ is:

✓
$64$
B
$32$
C
Cannot be determined
D
None of these

Answer

Correct option: A.

$64$

$\big[(-2)^{(-2)}\big]^{(-3)}$
$=(-2)^6=64$

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MCQ 761 Mark

The value of $\Big(\frac{-1}{216}\Big)^{-\frac{2}{3}}$ is:

✓
$36$
B
$-36$
C
$\frac{1}{36}$
D
$-\frac{1}{36}$

Answer

Correct option: A.

$36$

$\Big(\frac{-1}{216}\Big)^{-\frac{2}{3}}$
$=\bigg[\Big(\frac{-1}{6}\Big)^3\bigg]^{-\frac{2}{3}}$
$=\Big(\frac{-1}{6}\Big)^{3\text{x}-\frac{2}{3}}$
$=\Big(-\frac{1}{6}\Big)^{-2}$
$=\frac{1}{\Big(-\frac{1}{6}\Big)^2}$
$=\frac{1}{\frac{1}{36}}=36$

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MCQ 771 Mark

Mark $(\checkmark)$ against the correct answer in the following:
$\Big(\frac{-5}{4}\Big)^{-1}=?$

A
$\frac{3}{5}$
✓
$\frac{-3}{5}$
C
$\frac{5}{3}$
D
$\frac{-5}{3}$

Answer

Correct option: B.

$\frac{-3}{5}$

$\Big(\frac{-5}{3}\Big)^{-1}=\Big(\frac{3}{-5}\Big)^1$
$\Big[\text{Since}\Big(\frac{\text{a}}{\text{b}}\Big)^{-\text{n}}=\Big(\frac{\text{b}}{\text{a}}\Big)^\text{n}\Big]$
$=\Big(\frac{3}{-5}\times\frac{-1}{-1}\Big)=\frac{-3}{5}$

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MCQ 781 Mark

$(-1)^{11}$ value is:

A
$+1$
B
$0$
✓
$-1$
D
None

Answer

Correct option: C.

$-1$

The value of $(-1)^{11}$ is
$= (-1)^{1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1}$
$= (-1)^1 \times (-1)^1 \times (-1)^1 \times (-1)^1 \times (-1)^1 \times (-1)^1 \times (-1)^1 \times (-1)^1 \times (-1)^1 \times (-1)^1 \times (-1)^1$
$= -1$ As odd power of a negative number results in negative number only.

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MCQ 791 Mark

SImplify: $(256)^{0.16}\times(256)^{0.09}$

✓
$4$
B
$16$
C
$64$
D
$256.25$

Answer

Correct option: A.

$4$

$(256)^{0.16}\times(256)^{0.09}$
$=(256)^{(0.16+0.09)}$
$=(256)^{0.25}=(256)^{\frac{25}{100}}=(256)^{\frac{1}{4}}$
$=(4^4)^{\frac{1}{4}}=4^1=4$

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MCQ 801 Mark

$(2^{3^{4}})=$

A
$2^{4^{3}}$
B
$2^{3^{4}}$
✓
$\big(2^4\big)^3$
D
None of these.

Answer

Correct option: C.

$\big(2^4\big)^3$

$\big(2^3\big)^4$
$=2^{3\times4}$ $[\text{As}, (\text{x}^{\text{m}})^{\text{n}}=\text{x}^{\text{mn}}]$
$=2^{4\times3}$
$=(2^{4})^{3}$
Hence, the correct alternative is option $(c)$.

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MCQ 811 Mark

Square of $\big(\frac{-2}{3}\big)$ is:

A
$\frac{-2}{3}$
B
$\frac{2}{3}$
C
$\frac{-4}{9}$
✓
$\frac{4}{9}$

Answer

Correct option: D.

$\frac{4}{9}$

Square of $\frac{-2}{3}\text{ is }\big(\frac{-2}{3}\big)^{2}$
So, $\big(\frac{-2}{3}^{2}\big)=\big(\frac{-2}{3}\big)\times\big(\frac{-2}{3}\big)$
$=\frac{4}{9}$
[$\because$ multiplication of two rational number with same sign is always positive]

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MCQ 821 Mark

If $a = 25$, then $\text{a}^{25^{0}}+\text{a}^{0^{25}}$

A
$25$
✓
$26$
C
$24$
D
$0$

Answer

Correct option: B.

$26$

$\text{a}^{25^{0}}+\text{a}^{0^{25}}$
$=\text{a}^{1}+\text{a}^{0}$ $\Big(\text{As, }25^{0}=1\text{ and }0^{25}=0\Big)$
$=\text{a}+1$ $\Big(\text{As, }\text{a}^{0}=1\Big)$
$=25+1$
$=26$
Hence, the correct alternative is option $(b)$.

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MCQ 831 Mark

Find the value of $(6)^0 − (10)^0:$

A
$−4$
B
$2$
C
$1$
✓
$0$

Answer

Correct option: D.

$0$

$(6)^0− (10)^0= 1 − 1 = 0$

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MCQ 841 Mark

$a^m \times a^n$ is equal to:

A
$(a^2)^{mn}$
B
$a^{m-n}$
✓
$a^{m+n}$
D
$a^{mn}$

Answer

Correct option: C.

$a^{m+n}$

We know that, if $‘a’$ is a rational number, $m$ and $n$ are natural numbers, then.
$a^m \times a^n = a^{m+n}$

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MCQ 851 Mark

$x + 1$ is a factor of $xn+1$ only if:

✓
$N$ is an odd integer
B
$N$ is an even integer.
C
$N$ is a negative integer
D
$N$ is a positive integer.

Answer

Correct option: A.

$N$ is an odd integer

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MCQ 861 Mark

$\bigg[\Big\{\big(-\frac{1}{3}\big)\Big\}^{-2}\bigg]^{-1}=$

✓
$\frac{1}{81}$
B
$\frac{1}{9}$
C
$-\frac{1}{81}$
D
$-\frac{1}{9}$

Answer

Correct option: A.

$\frac{1}{81}$

$\bigg[\Big\{\big(-\frac{1}{3}\big)\Big\}^{-2}\bigg]^{-1}$
$\bigg[\Big\{\big(-\frac{1}{3}\big)^{2}\Big\}^{(-2)\times(-1)}\bigg]$ $[\text{As, }(\text{x}^{\text{m}})^{\text{n}}=\text{x}^{\text{mn}}\big]$
$=\Big(\frac{-1}{3}\Big)^{2\times2}$ $[\text{As, }(\text{x}^{\text{m}})^{\text{n}}=\text{x}^{\text{mn}}\big]$
$=\Big(\frac{-1}{3}\Big)^4$
$=\frac{(-1)^4}{3^4}$ $\Big[\text{As, }\Big(\frac{\text{x}}{\text{y}}\Big)^{\text{m}}=\frac{\text{x}^{\text{m}}}{\text{y}^{\text{m}}}\Big]$
$=\frac{1}{81}$
Hence, the correct alternative is option $(a)$.

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MCQ 871 Mark

Fill in the blanks
If $800=8\times10^8\times\text{x}^{\frac{-3}{2}},$ then $x =$ ____.

A
$10^2$
B
$10^3$
✓
$10^4$
D
$10^5$

Answer

Correct option: C.

$10^4$

$800=8\times10^8\times\text{x}^{\frac{-3}{2}}$
$\text{x}=(10^{-6})^\frac{-2}{3}$
$\Rightarrow\text{x}=10^4$

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MCQ 881 Mark

Mark $(\checkmark)$ tick against the correct answer in the following:
$(2^{-1}-4^{-1})^2=?$

✓
$4$
B
$-4$
C
$\frac{1}{16}$
D
$\frac{-1}{16}$

Answer

Correct option: A.

$4$

$\because(2^{-1}-4^{-1})^2=\Big(\frac{1}{2}-\frac{1}{4}\Big)^2$
$=\Big(\frac{2-1}{4}\Big)^2$
$=\Big(\frac{1}{4}\Big)^2=\frac{1}{4}\times\frac{1}{4}=\frac{1}{16}$

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MCQ 891 Mark

Mark $(\checkmark)$ tick against the correct answer in the following:
$(3^2-2^2)\times\Big(\frac{2}{3}\Big)^{-3}=?$

A
$\frac{45}{8}$
B
$\frac{8}{45}$
C
$\frac{8}{135}$
✓
$\frac{135}{8}$

Answer

Correct option: D.

$\frac{135}{8}$

$\because(3^2-2^2)\times\Big(\frac{2}{3}\Big)^{-3}=(9-4)\Big(\frac{3}{2}\Big)^3$
$=5\times\frac{3}{2}\times\frac{3}{2}\times\frac{3}{2}=\frac{135}{8}$

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MCQ 901 Mark

Which of the following has the largest value?

A
$0.0001$
B
$\frac{1}{10000}$
C
$\frac{1}{10^{6}}$
D
$\frac{1}{10^{6}}\div0.1$

Answer

For option $(a),0.0001=\frac{1}{10000}$
For option $(b),\frac{1}{10000}$
For option $(c),\frac{1}{10^{6}}=\frac{1}{10\times10\times10\times10\times10\times10}$
$=\frac{1}{1000000}$
For option $(d) , \frac{1}{10^{6}}+0.1=\frac{1}{0.1}\times\frac{1}{0.1}$
$=\frac{1}{10^{6}}\times\frac{10}{1}=\frac{10}{10^{6}}=\frac{1}{10^{5}}$
$=\frac{1}{10\times10\times10\times10\times10}$
$=\frac{1}{100000}$
The fraction whose denominator is smallest wil be largest.
Hence, $(a)$ and $(b)$ are the largest.

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MCQ 911 Mark

Simplify: $(-1)^19 + (-1)^{20} + (2)^5$

A
$34$
✓
$32$
C
$30$
D
$0$

Answer

Correct option: B.

$32$

$(-1)^{19} + (-1)^{20} + (2)^5$
$= (-1) + (1) + 2 × 2 × 2 × 2 × 2$
$= 32$

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MCQ 921 Mark

Mark $(\checkmark)$ tick against the correct answer in the following:
$\Bigg[\bigg\{\Big(-\frac{1}{2}\Big)^2\bigg\}^{-2}\Bigg]^{-1}=?$

✓
$\frac{1}{16}$
B
$16$
C
$\frac{-1}{16}$
D
$-16$

Answer

Correct option: A.

$\frac{1}{16}$

$\Bigg[\bigg\{\Big(-\frac{1}{2}\Big)^2\bigg\}^{-2}\Bigg]^{-1}=\Big(\frac{-1}{2}\Big)^{2\times(-2)\times(-1)}$
$=\Big(\frac{-1}{2}\Big)^4=\Big(\frac{-1}{2}\Big)\Big(\frac{-1}{2}\Big)\Big(\frac{-1}{2}\Big)\Big(\frac{-1}{2}\Big)$
$=\frac{1}{16}$

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MCQ 931 Mark

If $15 m^2n^3$ is divided by $5m^2n^2,$ then the index of quotient is:

A
Two
✓
One
C
Three
D
Zero

Answer

Correct option: B.

One

The index of the divisor $= 4$ and the index of dividend $= 5.$
$\therefore$ The index of the quotient $= 5 - 4 = 1$

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MCQ 941 Mark

Exponential form of $(-3) \times (-3) \times (-3)$ is:

A
$-3^3$
✓
$(-3)^3$
C
$3^3$
D
$(3)^3$

Answer

Correct option: B.

$(-3)^3$

$-3 \times -3 \times -3 = (-3)^3$

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MCQ 951 Mark

Mark $(\checkmark)$ against the correct answer in the following:
$\bigg\{\Big(\frac{1}{3}\Big)^{-3}-\Big(\frac{1}{2}\Big)^{-3}\bigg\}=?$

✓
$19$
B
$\frac{1}{19}$
C
$-19$
D
$\frac{-1}{19}$

Answer

Correct option: A.

$19$

$\Big[\text{Since}\Big(\frac{\text{a}}{\text{b}}\Big)^{-1}=\Big(\frac{\text{b}}{\text{a}}\Big)^1\Big]$
$\bigg\{\Big(\frac{1}{3}\Big)^{-3}-\Big(\frac{1}{2}\Big)^{-3}\bigg\}=\bigg\{\Big(\frac{3}{1}\Big)^3-\Big(\frac{2}{1}\Big)^3\bigg\}$
$=\big\{(3)^3-(2)^3\big\}$
$=(27-8)=19$

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MCQ 961 Mark

The expanded form of $a^6$ is:

A
$a \times 6$
✓
$a \times a \times a \times a \times a \times a$
C
$a \times a \times a \times a$
D
$a + a + a + a + a + a$

Answer

Correct option: B.

$a \times a \times a \times a \times a \times a$

$a^6= a \times a \times a \times a \times a \times a$

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MCQ 971 Mark

The product of $\sqrt[2]6$ and $\sqrt[2]24$ is:

A
$124$
B
$134$
✓
$12$
D
$154$

Answer

Correct option: C.

$12$

Given that, $\sqrt[4]6$ and $\sqrt[3]24$
Now, $\sqrt[2]6\times\sqrt[2]24=\sqrt[2]{144}=12$

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MCQ 981 Mark

Evaluate $(-32)^{\frac{2}{5}}$

✓
$4$
B
$64$
C
$8$
D
None of the above

Answer

Correct option: A.

$4$

As given $(-32)^{\frac{2}{5}}$
We can write $3^2$as $2^5$
$\Rightarrow(-2^5)^\frac{2}{5}$
$\Rightarrow(-2^{5.\frac{2}{5}})$
$\Rightarrow(-2^2)$
$\Rightarrow4$

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MCQ 991 Mark

What is the last digit in the expansion of $3^{4798}?$

✓
$1$
B
$3$
C
$7$
D
$9$

Answer

Correct option: A.

$1$

$3^{4798}= 3^{4(1197)}$
$= (3^4)^{1197}= (81)^{1197}$
Since the number in the units place of $81$ is $1,$
so the number in the units space is $(81)^{1197}$is the same as the number in the units place of $(1)^{1197}$ which is $1.$

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MCQ 1001 Mark

The value of $(256)^{0.16}× (256)^{0.09}$ is:

A
$64$
B
$256.25$
C
$16$
✓
$4$

Answer

Correct option: D.

$4$

$(256)^{0.16}\times(256)^{0.09}$
$=(256)^{0.25}=(256)^{\frac{1}{4}}=4$

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MATHS M.C.Q. [1 Marks Each]