Science Answer the questions.[Phy-1M]

$\text{p}=\frac{1}{\text{f}}=\frac{1}{0.08}=+1.25\text{D}$

$\text{p}=\frac{1}{\text{f}}=\frac{1}{0.5}=+2\text{D}$

$\text{P}=\frac{1}{\text{f}}$

$\text{f}=\frac{1}{\text{P}}=\frac{1}{(-2)}=-0.5\text{m}=-50\text{cm}$

$\text{P}=\frac{1}{\text{f}}$

$\text{f}=\frac{1}{\text{P}}=\frac{1}{0.2}=+5\text{m}$

$\text{p}=\frac{1}{\text{f}}=\frac{1}{0.25}=+4\text{D}$

Or

$\frac{1}{\text{v}}+\frac{1}{\text{u}}=\frac{1}{\text{f}}$

v = distance of image from mirror.

u = distance of object from mirror.

f = focal length of mirror.