- 60°.
Explanation:

Here. $\angle\text{A}\text{B}\text{N}= \angle\text{N}\text{B}\text{C}$ (angle of incidence = angle of reflection)
$\angle\text{B}\text{C}\text{O}=\angle\text{N}\text{B}\text{C}$ (alternate angles)
$\angle\text{M}\text{C}\text{B}=90^\circ-\angle\text{B}\text{C}\text{O}$ $\big(\angle\text{M}\text{C}\text{B}=$angle of incident for mirror QR$\big) $
= 60°
Now
$\big($$\angle\text{M}\text{C}\text{B}=\angle\text{M}\text{C}\text{D}=60^\circ $angle of reflection from mirror QR and angle of incidence = angle of reflection$\big)$