MCQ 1011 Mark
Which of the following are the factors of $a^2 - ab - ca + bc.$
- A
$(b + c) (c + a)$
- ✓
$(a - b) (a - c)$
- C
$a(a + b + c)$
- D
$(a + b) (b + c)$
AnswerCorrect option: B. $(a - b) (a - c)$
b. $(a - b) (a - c)$
Solution:
$= a^2 - ab - ca + bc$
$= a(a - b) - c(a - b)$
$= (a - b) (a - c)$
View full question & answer→MCQ 1021 Mark
Which of the following is the factorisation of $x^3 - x\ ?$
- A
$x(x - x^2)$
- B
$x[(1+ x) (1 - x)]$
- C
$x(x^2 - x)$
- ✓
$x(x + 1) (x - 1)$
AnswerCorrect option: D. $x(x + 1) (x - 1)$
d. $x[(x + 1) (x - 1)]$
Solution:
$x^3 - x$
Take x as common
$x(x^2 - 1)$
Property: $x^2 - a^2 = (x - a) (x + a)$
Applying the property
$x(x - 1) (x + 1)$
So, Factorization of $x^3 - x$ is $x(x - 1) (x + 1)$
View full question & answer→MCQ 1031 Mark
The value of $49^2$ is:
AnswerCorrect option: A. $(50)^2 - 2(50) (1) + (1)^2$
A. $(50)^2 - 2(50) (1) + (1)^2$
Solution:
$= 49^2 = (50 - 1)^2$
$= (50)^2 - 2(50) (1) + (1)^2$
View full question & answer→MCQ 1041 Mark
The factors of $6xy - 4y + 6 - 9x$ are:
- A
$(3x + 2) (2y + 3)$
- B
$(3x - 2) (2y - 3)$
- C
$(3x - 2) (2y + 3)$
- ✓
$(3x + 2) (2y - 3)$
AnswerCorrect option: D. $(3x + 2) (2y - 3)$
$= 6xy - 4y + 6 - 9x$
$= 6xy - 4y - 9x + 6$
$= 2y(3x - 2) - 3(3x - 2)$
$= (3x - 2) (2y - 3)$
View full question & answer→MCQ 1051 Mark
What is the value of $(3a + 4b) (a - b)$
- A
$3a^2 - ab - 4b^2$
- ✓
$3a^2 + ab - 4b^2$
- C
$(3a^2 + 4b^2)$
- D
$(3a^2 - 4b^2)$
AnswerCorrect option: B. $3a^2 + ab - 4b^2$
B. $3a^2 + ab - 4b^2$
Solution:
$(3a + 4b) (a - b)$
$\Rightarrow 3a(a - b) + 4b (a - b)$
$\Rightarrow 3a^2 - 3ab + 4ab - 4b^2$
$\Rightarrow 3a^2 + ab - 4b^2$
View full question & answer→MCQ 1061 Mark
Which of the following is the common factor of $21x^2y$ and $35xy^2\ ?$
AnswerC. $7xy$
Solution:
$21x^2y = 3 \times 7 \times x \times x \times y$
$35x,\ y^2 = 7 \times 5 \times x \times y \times y$
Thus, the common factors are common factors of $21x^2y$ and $35xy^2$ are $7, x, y.$
$(7 \times x \times y) = 7xy$
View full question & answer→MCQ 1071 Mark
Find the factors of $4p^4 + 12p + 8$
- A
$(p^2 + 3p + 2)$
- B
$4(p^2 + 3p + 2)$
- C
$(p + 1) (p + 2)$
- ✓
$4(p + 1) (p + 2)$
AnswerCorrect option: D. $4(p + 1) (p + 2)$
D. $4(p + 1) (p + 2)$
Solution:
$4 p^4+12 p+8$
Take $4$ as the common factor
$\Rightarrow 4\left( p ^2+3 p +2\right)$
Split the middle term
$\Rightarrow 4\left(p^2+2 p+p+2\right) $
$\Rightarrow 4(p(p+2)+1(p+2)) $
$\Rightarrow 4(p+1)(p+2)$
View full question & answer→MCQ 1081 Mark
The factorisation of $ax^2y + bxy^2 + cxyz$ is:
- ✓
$xy(ax + by + cz)$
- B
$axy(ax + by + cz)$
- C
$bxy(ax + by + cz)$
- D
$cxy(ax + by + cz)$
AnswerCorrect option: A. $xy(ax + by + cz)$
A. $xy(ax + by + cz)$
Solution:
$ax^2y + bxy^2 + cxyz = xy (ax + by + cz)$
View full question & answer→MCQ 1091 Mark
The common factor of $8a^2b^4c^2, 12a^4bc^4$ and $20a^3b^4$ is:
- A
$a^4b^4$
- B
$a^2b^2$
- C
$4a^2b^2$
- ✓
$4a^2b$
AnswerCorrect option: D. $4a^2b$
D. $4a^2b.$
Solution:
$8 a^2 b^4 c^2=2 \times 2 \times 2 \times a \times a \times b \times b \times b \times b \times c \times c $
$ 12 a^4 b c^2=2 \times 2 \times 3 \times a \times a \times a \times a \times b \times c \times c $
$ 20 a^3 b^4=2 \times 2 \times 5 \times a \times a \times a \times b \times b \times b \times b$
View full question & answer→MCQ 1101 Mark
The factorisation of $12x + 36$ is.
- A
$12(3x)$
- B
$12(3x + 1)$
- ✓
$12(x + 3)$
- D
$x(12 + 36x)$
AnswerCorrect option: C. $12(x + 3)$
$= 12x + 36$
$= 12 x + 12.3$
$=12(x + 3)$
View full question & answer→MCQ 1111 Mark
Factorise: $x^4 - (x - z)4$
AnswerCorrect option: C. $z(2x - z) (2x^2 - 2xz + z^2)$
C. $z(2x - z) (2x^2 - 2xz + z^2)$
View full question & answer→MCQ 1121 Mark
The common factor of $x^3y^2$ and $x^4y$ is:
- A
$x^4y^2$
- B
$x^4y$
- C
$x^3y^2$
- ✓
$x^3y$
AnswerCorrect option: D. $x^3y$
$x^3y^2 = x \times x \times x \times y \times y$
$x^4y = x \times x \times x \times x \times y$
View full question & answer→MCQ 1131 Mark
The common factor of $2a^2b^4c^2, 8a^4b^3c^4$ and $6a^3b^4c^2$ is:
- ✓
$2a^2b^3c^2$
- B
$6a^2b^3c^2$
- C
$8a^2b^3c^2$
- D
$a^4b^4c^4$
AnswerCorrect option: A. $2a^2b^3c^2$
A. $2a^2b^3c^2$
Solution:
$6 a^2 b^4 c^2=2 \times a \times a \times b \times b \times b \times b \times c \times c \times c \times c $
$8 a^4 b^3 c^4=2 \times 2 \times 2 \times a \times a \times a \times a \times b \times b \times b \times c \times c \times c \times c $
$6 a^3 b^4 c^2=2 \times 3 \times a \times a \times a \times b \times b \times b \times b \times c \times c$
View full question & answer→MCQ 1141 Mark
If $x^2 - x - 42 = (x + k) (x + 6),$ then $k =$
AnswerD. $-7$
Solution:
$x^2 - x - 42$
$= x^2 - 7x + 6x - 42$
$= x(x - 7) + 6(x - 7)$
$= (x - 7) (x + 6)$ $\therefore$ $k = -7$
View full question & answer→MCQ 1151 Mark
The common factor of $6x^3y^4z^2, 21x^2y$ and $15x^3$ is:
- A
$3x^3$
- B
$6x^3$
- ✓
$3x^2$
- D
$6x^2$
AnswerCorrect option: C. $3x^2$
Same as question number $14.$
View full question & answer→MCQ 1161 Mark
Find and correct the errors in the following mathematical statements.
$x(3x + 2) = 3x^2 + 2$
- ✓
$x(3x + 2) = 3x^2 + 2x$
- B
$x(3x + 2) = 3x^2$
- C
$x(3x + 2) = 5x^2+ 2x$
- D
AnswerCorrect option: A. $x(3x + 2) = 3x^2 + 2x$
A. $x(3x + 2) = 3x^2 + 2x$
View full question & answer→MCQ 1171 Mark
Divide as directed: $52pqr (p + q) (q + r) (r + p) ÷ 104pq (q + r) (r + p)$
AnswerCorrect option: B. $\frac{1}{2} \text{r}(\text{p}+\text{q})$
$\frac{1}{2} \text{r}(\text{p}+\text{q})$
View full question & answer→MCQ 1181 Mark
The common factor of $p^3q^4$ and $p^4q^3$ is:
- A
$p^4q^4$
- B
$p^4q$
- ✓
$p^3q^3$
- D
$p^3q^4$
AnswerCorrect option: C. $p^3q^3$
C. $p^3q^3$
Solution:
$p^3q^4 = p \times p \times p \times q \times q \times q \times q$
$p^4q^3 = p \times p \times p \times p \times q \times q \times q$
View full question & answer→MCQ 1191 Mark
One of the factors of $(a^2 - b^2)(c^2 - d^2) - 4abcd$ is:
- A
$ac - bd + bc - ad$
- B
$(ac - bd + bc + ad)$
- ✓
- D
View full question & answer→MCQ 1201 Mark
Which of the following statements is correct?
- ✓
$(a - 4)(a - 2) = a^2 + 8 - 6a$
- B
$(2p + 3q)(p - q) = 2p^2 - 3q^2$
- C
$\frac{3\text{p}^2}{3\text{p}^2}=0$
- D
$4(m - 5) = 4m - 5$
AnswerCorrect option: A. $(a - 4)(a - 2) = a^2 + 8 - 6a$
A. $(a - 4)(a - 2) = a^2 + 8 - 6a$
View full question & answer→MCQ 1211 Mark
Which of the following is a factor of $z^2 - 4z - 12?$
- A
$z + 6$
- B
$z - 6$
- C
$z^2 - 12$
- ✓
$z + 2$
AnswerCorrect option: D. $z + 2$
D. $z + 2$
View full question & answer→MCQ 1221 Mark
Tick $(\checkmark)$ the correct answer:
$3 + 23y - 8y^2 = \ ?$
- A
$(1 - 8y)(3 + y)$
- ✓
$(1 + 8y)(3 - y)$
- C
$(1 - 8y)(y - 3)$
- D
$(8y - 1)(y + 3)$
AnswerCorrect option: B. $(1 + 8y)(3 - y)$
B. $(1 + 8y)(3 - y)$
Solution:
$3+23 y-8 y^2 $
$=3+24 y-y-8 y^2 $
$ \{3 \times(-8)=-24,-24=24 \times(-1), 23=24-1\} $
$ =3(1+8 y)-y(1+8 y) $
$ =(1+8 y)(3-y)$
View full question & answer→MCQ 1231 Mark
The factorisation of $ax + bx - ay - by$ is:
- ✓
$(x - y) (a + b)$
- B
$(x + y) (a + b)$
- C
$(x - y) (a - b)$
- D
$(x + y) (a - b)$
AnswerCorrect option: A. $(x - y) (a + b)$
$= ax + bx - ay - by$
$= x(a + b) - y(a + b)$
$= (x - y)(a + b)$
View full question & answer→MCQ 1241 Mark
The factorisation of $12x^2y + 15xy^2$ is:
- A
$3xy^2(4x + 5y)$
- B
$3x^2y(4x + 5y)$
- C
$3x^2y^2(4x + 5x)$
- ✓
$3xy(4x + 5y)$
AnswerCorrect option: D. $3xy(4x + 5y)$
D. $3xy(4x + 5y)$
Solution:
$= 12x^2y + 15xy^2$
$= 3xy (4x + 5y)$
View full question & answer→MCQ 1251 Mark
Divide as directed: $5(2x + 1) (3x + 5) ÷ (2x + 1)$
- ✓
$5(3x + 5)$
- B
$(3x + 5)$
- C
$5$
- D
AnswerCorrect option: A. $5(3x + 5)$
$5(3x + 5)$
View full question & answer→MCQ 1261 Mark
The factors of $49p^2 - 36$ are:
- A
$(7p + 6)^2$
- B
$(7p - 6)^2$
- ✓
$(7p - 6 ) ( 7p + 6)$
- D
AnswerCorrect option: C. $(7p - 6 ) ( 7p + 6)$
C. $(7p - 6 ) ( 7p + 6)$
Solution:
$49p^2 - 36 = (7p)^2 - ( 6 )^2 = (7p - 6 ) ( 7p + 6)$
View full question & answer→MCQ 1271 Mark
The common factor of $x^2y^2$ and $x^3y^3$ is:
- ✓
$x^2y^2$
- B
$x^3y^3$
- C
$x^2y^3$
- D
$x^3y^2$
AnswerCorrect option: A. $x^2y^2$
A. $x^2y^2$
Solution:
$x^2y^2 = x \times x \times y \times y$
$x^3y^3 = x \times x \times x \times y \times y \times y$
View full question & answer→MCQ 1281 Mark
The common factor of $3a^2b^4c^2, 12b^2c^4$ and $15a^3b^4c^4$ is:
- A
$b^4c^4$
- ✓
$3b^2c^2$
- C
$15b^2c^4$
- D
$12b^2c^4$
AnswerCorrect option: B. $3b^2c^2$
B. $3b^2c^2$
Solution:
$3a^2b^4c^2 = 3 \times a \times a \times b \times b \times b \times b \times c \times c$
$12b^2c^4 = 2 \times 2 \times 3 \times b \times b \times c \times c \times c \times c$
$15a^3b^4c^4 = 3 \times 5 \times a \times a \times a \times b \times b \times b \times b \times c \times c \times c \times c$
View full question & answer→MCQ 1291 Mark
If $x = 2,\ y = -1$ then the value of $x^2 + 4xy + 4y^2$ is:
AnswerA. $0$
Solution:
$=x^2+4 x y+4 y^2=(x)^2+2(x)(2 y)+(2 y)^2 $
$ =(x+2 y)^2=\{2+2(-1)\}^2=0$
View full question & answer→MCQ 1301 Mark
The factors of $a^2 + b - ab - a$ are:
- A
$(a + 1)(a - b)$
- ✓
$(a - 1)(a - b)$
- C
$(a + b)(a - 1)$
- D
AnswerCorrect option: B. $(a - 1)(a - b)$
B. $(a - 1)(a - b)$
View full question & answer→MCQ 1311 Mark
Tick $(\checkmark)$ the correct answer of the following:
$(7a^2 - 63b^2) =\ ?$
- A
$(7a - 9b)(9a + 7b)$
- B
$(7a - 9b)(7a + 9b)$
- C
$9(a - 3b)(a + 3b)$
- ✓
$7(a - 3b)(a + 3b)$
AnswerCorrect option: D. $7(a - 3b)(a + 3b)$
D. $7(a - 3b)(a + 3b)$
Solution:
$7 a^2-63 b^2=7\left(a^2-9 b^2\right) $
$ =7\left\{(a)^2-(3 b)^2\right\}$
$ =7(a-3 b)(a+36)$
View full question & answer→MCQ 1321 Mark
Amrit and Pankaj expanded $(x - 5)^2.$ Amrit's answer is $x^2 - 25$ and Pankaj's answer is $x^2 -10x + 25.$ Which of the following statements is correct?
- A
Amrit's answer is correct.
- B
Pankaj's answer is wrong.
- C
- ✓
Pankaj's answer is correct.
AnswerCorrect option: D. Pankaj's answer is correct.
D. Pankaj's answer is correct.
View full question & answer→MCQ 1331 Mark
Tick $(\checkmark)$ the correct answer:
$(2 - 50x^2) = \ ?$
- A
$2(1 - 5x)^2$
- B
$2(1 + 5x)^2$
- C
$(2 - 5x)(2 + 5x)$
- ✓
$2(1 - 5x)(1 + 5x)$
AnswerCorrect option: D. $2(1 - 5x)(1 + 5x)$
D. $2(1 - 5x)(1 + 5x)$
Solution:
$2-50 x^2=2\left(1-25 x^2\right) $
$ =2\left\{(1)^2-(5 x)^2\right\} $.
$ =2(1-5 x)(1+5 x)$
View full question & answer→MCQ 1341 Mark
One of the factors of $(a2 - b^2) (c^2 - d^2) − 4abcd$ is:
- ✓
$(ac - bd + bc + ad)$
- B
$ac + bd + bc + ad$
- C
$ab + bd - bc - ad$
- D
AnswerCorrect option: A. $(ac - bd + bc + ad)$
A. $(ac - bd + bc + ad)$
View full question & answer→MCQ 1351 Mark
On factorising $14pq + 35pqr,$ we get:
- A
$pq(14 + 35r)$
- B
$p(14q + 35qr)$
- C
$q(14p + 35pr)$
- ✓
$7pq(2 + 5r)$
AnswerCorrect option: D. $7pq(2 + 5r)$
$14pq + 35pqr$
$= 2.7.p.q + 5.7.p.q.r$
$= 7pq(2 + 5r)$
View full question & answer→MCQ 1361 Mark
Tick $(\checkmark)$ the correct answer:
$pq^2 + q(p - 1) - 1 = \ ?$
- A
$(pq + 1)(q − 1)$
- B
$p(q + 1)(q − 1)$
- C
$q(p − 1)(q + 1)$
- ✓
$(pq − 1) (q + 1)$
AnswerCorrect option: D. $(pq − 1) (q + 1)$
D. $(pq − 1) (q + 1)$
Solution:
$pq^2 + q(p - 1) - 1$
$= pq^2 + pq - q - 1$
$= pq(q + 1) + -1(q + 1)$
$= (q + 1)(pq - 1)$
View full question & answer→MCQ 1371 Mark
The factorisation of $6x + 12y$ is:
- ✓
$6(x + 2y)$
- B
$3(x + 4y)$
- C
$2(3x + 12y)$
- D
AnswerCorrect option: A. $6(x + 2y)$
View full question & answer→MCQ 1381 Mark
Divide $x(4x^2 - 100)$ by $4x(x + 5)$
- ✓
$(x - 5)$
- B
$(x^2 - 25)$
- C
$(x + 5)$
- D
$(x + 5)^2$
AnswerCorrect option: A. $(x - 5)$
A. $(x - 5)$
Solution:
$\frac{\text{x}(4\text{x}^2-100)}{\text{x}(\text{x}-5)}$
$\Rightarrow\frac{\text{x}((2\text{x})^2-(10)^2)}{4\text{x}(\text{x}+5)}$
$\Rightarrow\frac{\text{x}(2\text{x}+10)(\text{2x}-10)}{4\text{x}(\text{x}+5)}$
$\Rightarrow\frac{2\text{x}(\text{x}+5)(2\text{xx}-10)}{2\times2\text{x}(\text{x}+5)}$
Cancel the common factors
$\Rightarrow\frac{2(\text{x}-5)}{2}=(\text{x}-5)$
View full question & answer→MCQ 1391 Mark
What is $12ab^2 \div c^3 8bc^2$
- ✓
$3abc$
- B
$3bc$
- C
$\frac{1}{3}\text{bc}$
- D
$\frac{1}{3}\text{abc}$
AnswerCorrect option: A. $3abc$
A. $3abc$
Solution:
The given expression can be written in fractional fonn as shown below,
$\frac{24\text{ab}^2\text{c}^2}{8\text{bc}^2},$ Now find the Highest Common Factor of the numerator and denominator,
$\Rightarrow \frac{8\times3\times\text{a}\times\text{b}^2\times\text{c}^2}{8\times\text{b}\times\text{c}^2}=3\text{abc}$
View full question & answer→MCQ 1401 Mark
When we factorise $^x2 + 5x + 6,$ then we get:
- ✓
$(x + 2) (x + 3)$
- B
$(x - 2) (x - 3)$
- C
$(x × 2) + (x × 3)$
- D
$(x × 2) - (x × 3)$
AnswerCorrect option: A. $(x + 2) (x + 3)$
A. $(x + 2) (x + 3)$
Solution:
The factors of a form:
$(x + a) (x + b) = x^2 + (a + b) x + ab$
$x^2+ 5x + 6$
$a + b = 5$ and $ab = 6$
$x^2 + 5x + 6 = (x + 2) (x + 3)$
View full question & answer→MCQ 1411 Mark
Find the value of x from $\frac{8\text{x}+4}{4}=8\text{x}$
- A
$-\frac{1}{6}$
- B
$\frac{1}{10}$
- C
$0$
- ✓
$\frac{1}{6}$
AnswerCorrect option: D. $\frac{1}{6}$
$\frac{8\text{x}+4}{4}=8\text{x}$
Multiply $4$ on both sides
$\Rightarrow 8x + 4 = 32x$
Bring like terms together
$\Rightarrow 4 = 32x - 8x$
$\Rightarrow 4 = 24x$
$\Rightarrow\text{x}=\frac{4}{24}=\frac{1}{6}$
View full question & answer→MCQ 1421 Mark
The common factor of $24a^3b^4, 36a^4c^4$ and $48a^3b^2c$ is:
- A
$24a^3$
- B
$36a^3$
- ✓
$12a^3$
- D
$48a^3$
AnswerCorrect option: C. $12a^3$
C. $12a^3$
Solution:
$24a^3b^4 = 2 \times 2 \times 2 \times 3 \times a \times a \times a \times b \times b \times b \times b$
$36a^4c^4 = 2 \times 2 \times 3 \times 3 \times a \times a \times a \times a \times c \times c \times c \times c$
$48a^3b^2c = 2 \times 2 \times 2 \times 2 \times 3 \times a \times a \times a \times b \times b \times c$
View full question & answer→MCQ 1431 Mark
Choose the factors of $15x^2 - 26x + 8$ from the following.
- A
$(3x - 4), (5x + 2)$
- ✓
$(3x - 4), (5x - 2)$
- C
$(3x + 4), (5x - 2)$
- D
$(3x + 4), (5x + 2)$
AnswerCorrect option: B. $(3x - 4), (5x - 2)$
B. $(3x - 4), (5x - 2)$
View full question & answer→MCQ 1441 Mark
The common factor of $a^2m^4$ and $a^4m^2$ is:
- A
$a^4m^4$
- ✓
$a^2m^2$
- C
$a^2m^4$
- D
$a^4m^2$
AnswerCorrect option: B. $a^2m^2$
B. $a^2m^2$
Solution:
$a^2m^4 = a \times a \times m \times m \times m \times m$
$a^4m^2 = a \times a \times a \times a \times m \times m$
View full question & answer→MCQ 1451 Mark
The factorisation of $(lm + l) + m + 1$ is:
- ✓
$(l + 1) (m + 1)$
- B
$(l - 1) (m - 1)$
- C
$(l + 1) (m - 1)$
- D
$(l - 1) (m + 1)$
AnswerCorrect option: A. $(l + 1) (m + 1)$
$= l(m + 1) + 1 (m + 1)$
$= (l + 1 ) (m + 1)$
View full question & answer→MCQ 1461 Mark
Find and correct the errors in the following mathematical statements.$ x + 2x + 3x = 5x$
- A
$x + 2x + 3x = 7x$
- ✓
$x + 2x + 3x = 6x$
- C
$x + 2x + 3x = 1/2x$
- D
$x + 2x + 3x = 5x$
AnswerCorrect option: B. $x + 2x + 3x = 6x$
$x + 2x + 3x = 6x$
View full question & answer→MCQ 1471 Mark
One of the factors of $x^4 + 4$ is:
- ✓
$x^2 - 2x +2$
- B
$x^2 + 2$
- C
$x^2 - 2$
- D
AnswerCorrect option: A. $x^2 - 2x +2$
A. $x^2 - 2x +2$
View full question & answer→MCQ 1481 Mark
The value of $3.5 \times 3.5 - 2.5 \times 2.5$ is:
AnswerValue$ = (3.5 + 2.5) (3.5 - 2.5) = 6$
View full question & answer→MCQ 1491 Mark
The factorisation of $a(x + y + z) + b(x + y + z) + c(x + y + z)$ is:
- ✓
$(a + b + c) (x + y + z)$
- B
$(ab + bc + ca) (x + y + z)$
- C
$(xy + yz + zx) (a + b + c)$
- D
AnswerCorrect option: A. $(a + b + c) (x + y + z)$
$a(x + y + z) + b(x + y + z) + c(x + y + z)$
$= (x + y + z) (a + b + c)$
View full question & answer→MCQ 1501 Mark
The common factor of $36p^2q^3x^4, 48pq^3x^2$ and $54p^3q^3x^4$ is:
- ✓
$6pq^3x^2$
- B
$36pq^3x^2$
- C
$54pq^3x^2$
- D
$48pq^3x^2$
AnswerCorrect option: A. $6pq^3x^2$
A. $6pq^3x^2$
Solution:
$36 p^2 q^3 x^4=2 \times 2 \times 3 \times 3 \times p \times p \times q \times q \times q \times x \times x \times x \times x $
$ 48 p q^3 x^2=2 \times 2 \times 2 \times 2 \times 3 \times p \times q \times q \times q \times x \times x $
$ p^3 q^3 x^4=p \times p \times p \times q \times q \times q \times x \times x \times x \times x$
View full question & answer→