Question 15 Marks
1. Identify the pairs of compounds which are functional group isomers.

2. Explain, how is the electronegativity of carbon atoms related to their state of hybridization in an organic compound.

2. Explain, how is the electronegativity of carbon atoms related to their state of hybridization in an organic compound.
Answer
View full question & answer→1. All the seven compounds given have the same molecular formula, so each alcohol is a functional group isomer of each ether given and visa-versa. Functional group isomers are a type of structural isomers having the same molecular formula but different functional groups. In the given structures, I, II, III, IV represent alcohols and V, VI, VII are ethers. Hence, I and V, I and VI, I and VII, II and V, II and VI, II and VII, III and V, III and VI, etc.
2. If C is sp hybridized then S character is $50 \%$.
If C is $sp ^2$ hybridized then S character is $33 \%$.
If C is $sp ^3$ hybridized then S character is $25 \%$.
Electronegativity of carbon is directly proportional to ' $s$ ' character.
Hence, sp hybridized carbon has strong S character.
We know that, s electrons are more strongly attracted by nucleus than p-electrons as they lie closer to nucleus.. Thus, electronegativity of carbon increases with increase in ' $s$ ' character.
2. If C is sp hybridized then S character is $50 \%$.
If C is $sp ^2$ hybridized then S character is $33 \%$.
If C is $sp ^3$ hybridized then S character is $25 \%$.
Electronegativity of carbon is directly proportional to ' $s$ ' character.
Hence, sp hybridized carbon has strong S character.
We know that, s electrons are more strongly attracted by nucleus than p-electrons as they lie closer to nucleus.. Thus, electronegativity of carbon increases with increase in ' $s$ ' character.


