Question 13 Marks
Calculate the change in the Kinetic energy of a moving body if its velocity is reduced to $1/3rd$ of the initial velocity.
Answer
View full question & answer→$K . E _1=\frac{1}{2} mv ^2$
K.E. $2=\frac{1}{2} m \left(\frac{1}{3} v \right)^2$
$KE_1 : KE_2$
$\frac{1}{2} mv ^2=\frac{1}{2} m \frac{1 v ^2}{9}$
$\frac{ mv ^2}{2}=\frac{ mv ^2}{18}=18: 2=9: 1$
K.E. $2=\frac{1}{2} m \left(\frac{1}{3} v \right)^2$
$KE_1 : KE_2$
$\frac{1}{2} mv ^2=\frac{1}{2} m \frac{1 v ^2}{9}$
$\frac{ mv ^2}{2}=\frac{ mv ^2}{18}=18: 2=9: 1$


