If A(4, 2), B(6, 5) and C(1, 4) be the verteces of $\triangle\text{ABC}$ and AD is a median, then the coordinates of D are:
- A$\Big(\frac{5}{2},3\Big)$
- B$\Big(5,\frac{7}{2}\Big)$
- ✓$\Big(\frac{7}{2},\frac{9}{2}\Big)$
- D$\text{none of these}$
Answer: C.
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