Question 13 Marks
Explain the process of breakdown of glucose in a cell:
- In the presence of oxygen.
- In the absence of oxygen.
Answer
View full question & answer→The first step is the break - down of glucose, a six-carbon molecule, into a three-carbon molecule called pyruvate. This process takes place in the cytoplasm. Further, the pyruvate may be converted into ethanol and carbon dioxide. This process takes place in yeast during fermentation. Since this process takes place in the absence in air (oxygen), it is called anaerobic respiration. Break-down of pyruvate using oxygen takes place in the mitochondria. This process breaks up the three-carbon pyruvate molecule to give three molecules of carbon dioxide. The other product is water. Since this process takes place in the presence of air (oxygen), it is called aerobic respiration. The release of energy in this aerobic process is a lot greater than in the anaerobic process.$\text{Glucose}\rightarrow\text{Pyruvate}$
$\text{Pyruvate} \xrightarrow[\text{of oxygen}]{\text{In presence}}\text{CO}_{2}+\text{H}_{2}\text{O} + \text{Energy}$
$\text{Pyruvate}\xrightarrow[\text{of oxygen}]{\text{In absence}}\text{C}_{2}\text{H}_{5}\text{OH + CO}_{2}+ \text{ Energy}$
$\text{Pyruvate} \xrightarrow[\text{of oxygen}]{\text{In presence}}\text{CO}_{2}+\text{H}_{2}\text{O} + \text{Energy}$
$\text{Pyruvate}\xrightarrow[\text{of oxygen}]{\text{In absence}}\text{C}_{2}\text{H}_{5}\text{OH + CO}_{2}+ \text{ Energy}$





