If distance between lines $(x-2 y)^2+k(x-2 y)=0$ is 3 units, then $k=$
- A± 3
- B$\pm 5 \sqrt{5}$
- C± 5
- ✓$\pm 3 \sqrt{5}$
Answer: D.
View full solution →282 questions across 7 question groups — pick any mix to generate a Maths paper with step-by-step answer keys.
MCQ
150 Q→02Answer the following questions in short.
27 Q→03Solve the Following Question.(2 Marks)
38 Q→04Solve the Following Question.(3 Marks)
40 Q→05Solve the Following Question.(4 Marks)
18 Q→06Do as instructed
3 Q→07Solve the Following Question.(5 Marks)
6 Q→One sample from each question group in this chapter. Select any group above to see the full set with answer keys.
Answer: D.
View full solution →Answer: D.
View full solution →Answer: D.
View full solution →Answer: C.
View full solution →Answer: B.
View full solution →repersented by $a x^2+2 h x y+b y^2=0$ is $\left|\frac{a x_1^2+2 h x_1 y_1+b y_1^2}{\sqrt{(a-b)^2+4 h^2}}\right|$
angle of $\alpha$ with the line $x+y=0$ is $x^2+2(\sec 2 \alpha) x y+y^2=0$.
OR
Show that, one of the lines represented by $a x^2+2 h x y+b y^2=0$ will make an anqle of the same measure with the X-axis as the other makes with the Y-axis, if a = ± b.
show that $a^2 b+a b^2+8 h^3=6 a b h$.
Pick question groups from the list above, set marks and difficulty, and export a branded PDF with step-by-step answer keys. First 3 chapters free — no signup.