
$\frac{2}{3}+\frac{4}{3}=\frac{2+4}{3}=\frac{6}{3}$= 2
$\frac{1}{3}+\frac{2}{3}=\frac{1+2}{3}=\frac{3}{3}$= 1
$\frac{2}{3}-\frac{1}{3}=\frac{2-1}{3}=\frac{1}{3}$
$\frac{4}{3}-\frac{2}{3}=\frac{4-2}{3}=\frac{2}{3}$
and $\frac{1}{3}+\frac{2}{3}=\frac{3}{3}$ = 1
Hence, the above-given number box can be completed as:
| $\frac{2}{3}$ | $\frac{4}{3}$ | 2 |
| $\frac{1}{3}$ | $\frac{2}{3}$ | 1 |
| $\frac{1}{3}$ | $\frac{2}{3}$ | 1 |








