Question 12 Marks
Answer
$
\begin{aligned}
& MLT^{-2}=20 N \ldots(i) \\
& ML^2 T^{-2}=200 J \ldots(ii)\\
& LT^{-1}=5 ms^{-1} \ldots(iii)
\end{aligned}
$
Dividing (ii) by (i),
$
L=\frac{200}{20}=10 m
$
Putting the value of L in (iii),
$
10 T^{-1}=5 \text { or } T=2 s
$
From (i),
$
M \times 10 \times(2)^{-2}=20 \text { or } M=8 kg
$
View full question & answer→$
\begin{aligned}
& MLT^{-2}=20 N \ldots(i) \\
& ML^2 T^{-2}=200 J \ldots(ii)\\
& LT^{-1}=5 ms^{-1} \ldots(iii)
\end{aligned}
$
Dividing (ii) by (i),
$
L=\frac{200}{20}=10 m
$
Putting the value of L in (iii),
$
10 T^{-1}=5 \text { or } T=2 s
$
From (i),
$
M \times 10 \times(2)^{-2}=20 \text { or } M=8 kg
$