A person standing near the edge of the top of a building throws two balls $A$ and $B.$ The ball $A$ is thrown vertically upward and $B$ is thrown vertically downward with the same speed. The ball A hits the ground with a speed $\mathrm{v}_{\mathrm{A}}$ and the ball B hits the ground with a speed $\mathrm{v}_{\mathrm{B}}.$ We have:
- A$\mathrm{v}_{\mathrm{A}} > \mathrm{v}_{\mathrm{B}}$
- B$\mathrm{v}_{\mathrm{A}} < \mathrm{v}_{\mathrm{B}} $
- ✓$\mathrm{v}_{\mathrm{A}} = \mathrm{v}_{\mathrm{B}}$
- DThe relation between $\mathrm{v}_{\mathrm{A}}$ and $\mathrm{v}_{\mathrm{B}}$ depends on height of the building above the ground.
Answer: C.
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