$0.08 \mathrm{~kg}$ air is heated at constant volume through $5^{\circ} \mathrm{C}$. The specific heat of air at constant volume is $0.17 \mathrm{kcal} / \mathrm{kg}^{\circ} \mathrm{C}$ and $\mathrm{J}=4.18$ joule $/ \mathrm{cal}$. The change in its internal energy is approximately.
JEE MAIN 2024, Diffcult
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$ \mathrm{Q}=\Delta \mathrm{U} \text { as work done is zero [constant volume] } $
$ \Delta \mathrm{U}=\mathrm{ms} \Delta \mathrm{T} $
$ =0.08 \times(170 \times 4.18) \times 5 $
$ \simeq 284 \mathrm{~J}$
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