$0.08 \mathrm{~kg}$ air is heated at constant volume through $5^{\circ} \mathrm{C}$. The specific heat of air at constant volume is $0.17 \mathrm{kcal} / \mathrm{kg}^{\circ} \mathrm{C}$ and $\mathrm{J}=4.18$ joule $/ \mathrm{cal}$. The change in its internal energy is approximately.
A $318 \mathrm{~J}$
B $298 \mathrm{~J}$
C $284 \mathrm{~J}$
D $142 \mathrm{~J}$
JEE MAIN 2024, Diffcult
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C $284 \mathrm{~J}$
c $ \mathrm{Q}=\Delta \mathrm{U} \text { as work done is zero [constant volume] } $
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