$\therefore \,\,\frac{{\text{W}}}{{\text{E}}}\,\, = \,\,\frac{Q}{{96500}}\,\, \Rightarrow \,\,\frac{{3.17}}{E}\,\, = \,\,\frac{{0.1\,\, \times \,\,96500}}{{96500}}$
$E\,\, = \,\,31.7$
$Zn|ZnS{O_4}_{(0.01{\kern 1pt} M)}||CuS{O_4}_{(1.0{\kern 1pt} M)}|Cu$
(આપેલ: $ E^oCr^{+3}| Cr = -0.75 \,V$ $E^o Fe^{+2} | Fe = - 0.45\, V)$
$Zn(s) + C{u^{2 + }}(0.1\,M) \to Z{n^{2 + }}(1\,M) + Cu(s)$ માટે $E_{cell}^o$ is $1.10\,volt$ હોય તો ${E_{cell}}$ જણાવો. $\left( {2.303\frac{{RT}}{F} = 0.0591} \right)$