where \(N\) is the number of turns in the coil, \(I\) is the current through the coil, \(B\) is the uniform magnetic field, \(A\) is the area of the coil and \(\theta\) is the angle between the direction of the magnetic field and nomal to the plane of the coil. Here, \(N=50, I=2\, \mathrm{A},\)

\(A=0.12\, \mathrm{m} \times 0.1\, \mathrm{m}=0.012\, \mathrm{m}^{2}\)

\(B=0.2\, \mathrm{Wb} / \mathrm{m}^{2} \text { and } \theta=90^{\circ}-30^{\circ}=60^{\circ}\)

\(\therefore \quad \tau =(50)(2\, \mathrm{A})\left(0.012\, \mathrm{m}^{2}\right)\left(0.2\, \mathrm{Wb} / \mathrm{m}^{2}\right) \sin 60^{\circ} \)

\(=0.20\, \mathrm{N} \mathrm{m}\)