\({K_a} = 0.1 \times {\left( {\frac{1}{{100}}} \right)^2} = {10^{ - 5}}\)
જો તે \(10\)\(\% \) આયનીકરણ થાય તો સાંદ્રતા
\({10^{ - 5}} = C \times {\left( {\frac{{10}}{{100}}} \right)^2}\,\,\, \Rightarrow \,\,\,\,{10^{ - 5}} = C \times {10^{ - 2}}\,\,\,\,\,\,\therefore \,\,\,\,C = {10^{ - 3}}\,\,i.e.\,\,0.001\,M\)
(ગ્લીસરીન માટે $Ka_1 = 4.5\times 10^{-3}$, $Ka_2 =1.7 \times 10^{-10}$ )
[આપેલ : $\sqrt{2}=1.41$ ]