(ઉપયોગ $R =8.31\, J\, K ^{-1}\, mol ^{-1} ; \log 2=0.3010$. In $10=$ $2.3, \log 3=0.477$ )
$(1)$ $ A_{2(g)} + 3B_{2(g)} $ $\rightleftharpoons$ $2AB_{3(g)} $ |
$(i)$ $(RT)^{-2}$ |
$(2)$ $ A_{2(g)} + B_{2(g)} $ $\rightleftharpoons$ $ 2AB_{(g)}$ |
$(ii)$ $ (RT)^0$ |
$(3)$ $A_{(s)} + 1.5 B_{2(g)} $ $\rightleftharpoons$ $ AB_{3(g)}$ |
$(iii)$ $(RT)^{1/2}$ |
$(4)$ $AB_{2(g)} $ $\rightleftharpoons$ $AB_{(g)} + 0.5B_{(g)}$ |
$(iv)$ $(RT)^{-1/2}$ |
$\mathrm{A}_{2}(\mathrm{g})+\mathrm{B}_{2}(\mathrm{g}) \rightleftharpoons \mathrm{X}_{2}(\mathrm{g}) \Delta_{r} \mathrm{H}=-\mathrm{X} \mathrm{kJ} ?$