d
Pressure is defined as normal force per unit area.

Force is calculated as change in \( momentum/time.\)

By this answer is \(2 \mathrm{N} / \mathrm{m}^{2}\)

None of the option matches so this question must be Bonus.

Detailed solution is as following:

\(Magnitude\, of\, change\, in\, momentum \,per\, collision\) \(=2\) \(mv\)

Pressure \(=\frac{\text { Force }}{\text { Area }}=\frac{N(2 m v)}{1}\)

\({=\frac{10^{22} \times 2 \times 10^{-26} \times 10^{4}}{1}} \)

\({=2 \mathrm{N} / \mathrm{m}^{2}}\)