${MCl}_{3} \cdot 2 {~L} \stackrel{{Ex} . {AgNO}_{3}}{\longrightarrow} 1 {~mole} \text { of } {AgCl}$
Its means that one ${Cl}^{-}$ion present in ionization sphere.
$\therefore \text { formula }=\left[{MCl}_{2} {~L}_{2}\right] {Cl}$
For octahedral complex coordination no. is $6$
$\therefore {L}$ act as bidentate ligand
$(K)\ K_3\ [Fe (CN)_6]$
$(L)\ [Co (NH_3)_6]\ Cl_3$
$(M)\ Na_3\ [Co (ox_3)]$
$(N)[ Ni (H_2O)_6] Cl_2$
$(O)\ K_2\ [Pt (CN_4)]$
$(P)\ [Zn (H_2O)_6]\ (NO_3)_2$
(પરમાણુ ક્રમાંક : $Ni = 28$)