Mass of the shell, \(m=0.020 \,kg\)
Muzzle speed of the shell, \(v=80 \,m / s\)
Recoil speed of the gun \(=V\)
Both the gun and the shell are at rest initially.
Initial momentum of the system \(=0\)
Final momentum of the system \(=m v-M V\)
Here, the negative sign appears because the directions of the shell and the gun are opposite to each other.
According to the law of conservation of momentum:
Final momentum \(=\) Initial momentum
\(m v-M V=0\)
\(\therefore V=\frac{m v}{M}\)
\(=\frac{0.020 \times 80}{100 \times 1000}=0.016 \,m / s\)
[$\sin \left(35^{\circ}\right)=0.573, \cos \left(35^{\circ}\right)=0.819$ $\left.\sin \left(110^{\circ}\right)=0.939, \cos \left(110^{\circ}\right)=-0.342\right]$