a
(a)As truck is moving on an incline plane therefore only component of weight \((mg\sin \theta )\) will oppose the upward motion Power = force \(×\) velocity = \(mg\sin \theta \times v\)
\( = 30000 \times 10 \times \left( {\frac{1}{{100}}} \right) \times \frac{{30 \times 5}}{{18}} = 25\,kW\)