$($ મોલર દળ $Fe=56\, g\, mol^{-1}$, $Cl=35.5\, g\, mol^{-1})$
Moles of \(Fe(OH)_3\) \( = \frac{{weight\,in\,g}}{{M.\,weight\,of\,Fe{{(OH)}_3}}}\)
\( = \frac{{2.14\,g}}{{107\,g/mol}} = 0.02\,mol.\)
\(1.0\) mole of \(Fe(OH)_3\) is obtained from \(= 1.0\) mole of \(FeCl_3\)
\(0.02\) mole of \(Fe(OH)_3\) is obtained from \(0.02\) mole of \(FeCl_3\)
Molarity
\( = \frac{{No.\,of\,moles}}{{Volume\,in\,L}} = \frac{{0.02\,mole}}{{0.1\,L}} = 0.2\,M\)
[પરમાણ્વીય દળ: $K : 39.0\, u ; O : 16.0 \,u ; H : 1.0\, u ]$