\(\Rightarrow \lambda=2 l \ldots(i)\)
Given, \(l=100 cm , v=2.53 kHz =2.53 \times 10^{3} Hz\)
We know that,
\(v=v \lambda\)
\(=v \times 2 l\) [from equation \((i)]\)
\(=2.53 \times 10^{3} \times 2 \times 100 \times 10^{-2}\)
\(=5.06 \times 10^{3} m / s\)
\(=5.06 km / s\)