MCQ
$108\,g\,Al$ and $213\,g\,MnO$ was heated to initiate the reaction 

$2 Al + 3MnO \to Al_2O_3 + 3Mn$

Which of the following is correct? (Atomic weights of $Mn = 55$ and $Al = 27$)

  • A
    $Al$ is limiting reagent
  • $102\,g\,Al_2O_3$ is formed
  • C
    $MnO$ is excess reagent
  • D
    None of these

Answer

Correct option: B.
$102\,g\,Al_2O_3$ is formed
b
$\begin{gathered}
  \mathop {}\limits_{Moles\,\,:\,} \mathop {2Al}\limits_{4\,moles}  + \mathop {3MnO}\limits_{3\,moles}  \to A{l_2}{O_3} + 3Mn \hfill \\
   \hfill \\ 
\end{gathered} $

$\frac{n}{\text { st. coefficient }}: \frac{4}{2}>\frac{3}{3}$

$MnO$ is limiting reagent

$\mathrm{n}_{\mathrm{A} \mathrm{l}_{2} \mathrm{O}_{3}}=1\, \mathrm{mole}$

$\mathrm{n}_{\mathrm{Al}_{2} \mathrm{O}_{3}}=1 \times 102 \,\mathrm{g}=102 \,\mathrm{g}$

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