\(Y = 2 \times {10^{11}}N{m^{ - 2}}\)

\({\ell _0} = 1.0m\)

\(radius\,r = 10mm = {10^{ - 2}}m\)

\(From\,formula,\,y = \frac{{Stress}}{{Strain}}\)

\( \Rightarrow \,\,Strain = \frac{{Stress}}{Y} = \frac{F}{{AY}}\)

\( = \frac{{{{10}^5}}}{{\pi {r^2}Y}} = \frac{{{{10}^5}}}{{3.14 \times {{10}^{ - 4}} \times 2 \times {{10}^{11}}}}\)

\( = \frac{1}{{628}}\)

\(Therefor\% strain = \frac{1}{{628}} \times 10 = 0.16\% \)