$(A)$ $CH _{3} COOH$
$(B)$ $HCHO$
$(C)$ $CH _{3} OOCH _{3}$
$(D)$ $CH _{3} CHO$
\(\% O =\frac{60}{116} \times 100=51.7\)
\(\% C =\frac{48.5}{116} \times 100=41.8\)
Relative atomicities \(=\)
\(H \Rightarrow 6.5\)
\(O \Rightarrow \frac{51.7}{16}=3.25\)
\(C \Rightarrow \frac{41.8}{12}=3.5\)
Emperically formula is approx. \(CH _{2} O\)
\((A)\) \(C _{2} H _{4} O _{2}\) \((B)\) \(CH _{2} O\) relate to this formula.
[આણ્વિય દળ : ${H}: 1.0, {C}: 12.0, {O}: 16.0]$