\(W_{\text {friction }}+W_{\text {spring }}=0-\frac{1}{2} m v^{2}\)
\(-\frac{90}{100}\left(\frac{1}{2} m v^{2}\right)+W_{\text {Spring }}=-\frac{1}{2} m v^{2}\)
\({W}_{\text {spring }}=-\frac{10}{100} \times \frac{1}{2} {mv}^{2}\)
\(-\frac{1}{2} {kx}^{2}=-\frac{1}{20} {mv}^{2}\)
\(\Rightarrow {k}=\frac{40000 \times(20)^{2}}{10 \times(1)^{2}}=16 \times 10^{5}\)
$\text { [ } g=10 \mathrm{~m} / \mathrm{s}^2]$લો.