MCQ
$150\, g\, CaCO_3$ sample was taken. On its complete decomposition $56\, g\, CaO$ is produced. The $\%$ purity of sample is .............. $\%$
- A$33.33$
- ✓$37.33$
- C$50$
- D$75$
$\mathrm{CaCO}_{3} \longrightarrow \mathrm{CaO}+\mathrm{CO}_{2}$
Mass of $\mathrm{CaCO}_{3}=150 \mathrm{g}$
Mass of $\mathrm{CaO}=56 \mathrm{g}$
Percentage Purity of Sample $=? ? ?$
Percentage Purity $=\frac{\text { Mass of pure product }}{\text { Mass of impure product }} \times 100 \%$
So, $\%$ Purity $=\frac{56 g}{150 g} \times 100 \%=0.37333 \times 100 \%=37.33 \%$
So the correct answer should be $(b)$ but it should be $37.33 \%$
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