$16$ tunning forks are arranged in the order of increasing frequencies. Any two successive forks give $8$ beats per sec when sounded together. If the frequency of the last fork is twice the first, then the frequency of the first fork is
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(a) Using $n_{Last} = n_{First} + (N -1)x$
$ ==> 2n = n + (16 -1) × 8 ==> n = 120 Hz$
$ ==> 2n = n + (16 -1) × 8 ==> n = 120 Hz$
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