MCQ
$1\,g$ of a liquid is converted to vapour at $3 \times 10^5\,Pa$ pressure. If $10 \%$ of the heat supplied is used for increasing the volume by $1600\,cm ^3$ during this phase change, then the increase in internal energy in the process will be $............\,J$
  • $4320$
  • B
    $432000$
  • C
    $4800$
  • D
    $4..32$

Answer

Correct option: A.
$4320$
a
Work done $= P \Delta V$

$=3 \times 10^5 \times 1600 \times 10^{-6}$

$=480\,J$

Only $10 \%$ of heat is used in work done.

Hence $\Delta Q=4800\,J$

The rest goes in internal energy, which is $90\,\%$ of heat.

Change in internal energy $=0.9 \times 4800=4320\,J$

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