\(\mathrm{C}_{3} \mathrm{H}_{8}+5 \mathrm{O}_{2} \rightarrow 3 \mathrm{CO}_{2}+4 \mathrm{H}_{2} \mathrm{O}\)
\(22.4 \mathrm{L} \quad 5 \times 22.4 \mathrm{L}\)
Therefore, to burn \(22.4 \mathrm{L} \;\mathrm{C}_{3} \mathrm{H}_{8}\) the oxygen required is \(=5 \times 22.4 \mathrm{L}\)
To burn \(1 \mathrm{L\;C}_{3} \mathrm{H}_{8}\) the oxygen required will be \(=5 \times 22.4 / 22.4=5 \mathrm{L}\)