$1\,mM$ પૃષ્ઠસકિય (surfactant) નુ $10\,mL$ દ્રાવણ, ધ્રુવીય પ્રકિયાર્થી પર $0.24\,cm^2$ આવરતુ એકસ્તર (monolayer) છે. ધ્રુવીય head ને સમધન તરીકે અંદાજવા માં આવે તો તેની ધારીની લંબાઇ શુ થશે ?

Question

JEE MAIN 2019, Diffcult

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Solution

a
$Moles = \frac{{MV\,ml}}{{1000}} = \frac{{{{10}^{ - 3}} \times 10}}{{1000}} = {10^{ - 5}}\,mole$

$10^{-5}$ $N_A$ molecules covering area $= 0.24\,cm^2$

$1$ molecules covering area $ = \frac{{0.24}}{{{{10}^{ - 5}}\,{N_A}}}$

$\frac{{0.24}}{{{{10}^{ - 5}}\, \times 6 \times {{10}^{23}}}} = {a^2}$

$a^2 = 4 \times 10^{-20}\,cm^2$

$a = 2 \times 10^{-10}\,cm$

$a = 2 \times 10^{-12}\,cm$

$a = 2\,pm$

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