$=-\frac{1}{2} \frac{\Delta\left[\mathrm{N}_2 \mathrm{O}_5\right]}{\Delta \mathrm{t}}=\frac{1}{4} \frac{\left[\mathrm{NO}_2\right]}{\Delta \mathrm{t}}=\frac{\Delta\left[\mathrm{O}_2\right]}{\Delta \mathrm{t}}$
$\mathrm{ROR}=-\frac{1}{2} \frac{\Delta\left[\mathrm{N}_2 \mathrm{O}_5\right]}{\Delta \mathrm{t}}=-\frac{1}{2} \frac{(2.75-3)}{30} \mathrm{molL}^{-1} \mathrm{~min}^{-1}$
$\mathrm{ROR}=-\frac{1}{2} \frac{(-0.25)}{30} \mathrm{molL}^{-1} \mathrm{~min}^{-1}$
$\text { ROR }=\frac{1}{240} \mathrm{molL}^{-1} \mathrm{~min}^{-1}$
$\text { Rate of formation of } \mathrm{NO}_2=\frac{\Delta\left[\mathrm{NO}_2\right]}{\Delta \mathrm{t}}=4 \times \mathrm{ROR}$
$=\frac{4}{240}=16.66 \times 10^{-3} \mathrm{molL}^{-1} \mathrm{~min}^{-1} \simeq 17 \times 10^{-3}$
$[X]$ $0.1\,M$, $[Y]$ $0.1\,M$ દર $\rightarrow 0.002\,Ms^{-1}$
$[X]$ $0.2\,M$, $[Y]$ $0.1\,M$ દર $\rightarrow 0.002\,Ms^{-1}$
$[X]$ $0.3\,M$, $[Y]$ $0.2\,M$ દર $\rightarrow 0.008\,Ms^{-1}$
$[X]$ $0.4\,M$, $[Y]$ $0.3\,M$ દર $\rightarrow 0.018\,Ms^{-1}$
તો દર નિયમ ......
$\left[\right.$ આપેલ $\left.\mathrm{R}=8.314 \,\mathrm{JK}^{-1} \,\mathrm{~mol}^{-1}\right]$