MCQ
$2 \mathrm{SO}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{SO}_{3}(\mathrm{~g})$

The above reaction is carried out in a vessel starting with partial pressure $\mathrm{P}_{\mathrm{SO}_{2}}=250\, \mathrm{~m}$ $bar,$ $\mathrm{P}_{0_{2}}=750 \,\mathrm{~m}$ $bar$ and $\mathrm{P}_{\mathrm{SO}_{3}}=0 \,\mathrm{bar}$. When the reaction is complete, the total pressure in the reaction vessel is $.....\mathrm{m}$ $bar.$ (Round off to the Nearest Integer).

  • $875$
  • B
    $550$
  • C
    $425$
  • D
    $930$

Answer

Correct option: A.
$875$
a
$\quad\quad\quad\quad\quad2 \mathrm{SO}_{2}(\mathrm{~g})+ \mathrm{O}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{So}_{3}(\mathrm{~g})$

$\text { Initial } \quad 250 \mathrm{~m} \text { bar } \quad750 \mathrm{~m} \text { bar } \quad\quad\quad0$

$\text { (L.R.) }$

$\text { Final } \quad-250 \,\mathrm{~m}\, \text { bar } -125 \mathrm{~m} \text { bar } \quad250 \mathrm{~m} \,\mathrm{bar}$

$\quad\quad\quad\quad\quad\quad\overline{0} \quad\quad\quad \,\overline{625 \mathrm{~m} \mathrm{bar}} \,\quad\quad \overline{250 \mathrm{~m} \mathrm{bar}}$

$\therefore$ Final total pressure $=625+250=875\, \mathrm{~m}$ $bar$

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